A first order lineal equation has the form u′=a(t)u+b(t) where a and b are continuous functionsfrom an interval [α,β] to the real line.
b is called the inhomogeneity of the problem, and the equation where b=0 is called the associated homogeneous equation. u′=a(t)u
A solution of a first order linear equation is a C1 function from [α,β] to the real line such that the equation is satisfied at all times. We will denote the set of solutions of an equation with inhomogeneity b as Σb, and the solutions of the associated homogeneous system as Σ0.
Properties of the space of solutions
Σ0 is a vector space; that is, it satifies the principle of superposition: linear combinations of solutions are solutions.
Σb is an [-affine_space] parallel to Σ0. That is, it satifies that the difference of any two solutions are in Σ0, and any element in Σ0 plus other element in Σb is an element from Σb.
First order linear equations of constant coefficients
One special kind of linear equations are those in which the coefficients a and b are constant numbers Such linear equations are always resoluble. u′=au+b
To solve them, we first have to solve the associated homogeneous equation u′=au.
This has as a solution the functions ke∫tt0a for k constant and t0∈[α,β].
We can find a concrete solution of the inhomogeneous equation using variation of coefficients. We consider as a candidate to a solution the function u=h˙v, for h a solution of the homogeneous system such as e∫tt0a.
Then if we plug u into the equation we find that u′=(hv)′=h′v+hv′=au+b=a(hv)+b Since h∈Σ0, h′=ah, thus v′=bh−1=be−∫tt0a Therefore we can integrate and we arrive to: v=∫tt0be∫stads By the affinity of Σb, we can parametrize it by ke∫tt0a+∫tt0be∫stads for k constant.
Comments
Faisal AlZaben
Glad to see this! Second order soon?
Jaime Sevilla Molina
Might as well do it! No promises though.