Let ⟨P,≤P⟩ and ⟨Q,≤Q⟩ be posets. Then a function ϕ:P→Q is said to be monotone (alternatively, order-preserving) if for all s,t∈P, s≤Pt implies ϕ(s)≤Qϕ(t).
Positive example
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Here is an example of a monotone map ϕ from a poset P to another poset Q. Since ≤P has two comparable pairs of elements, (c,a) and (b,a), there are two constraints that ϕ must satisfy to be considered monotone. Since c≤Pa, we need ϕ(c)=u≤Qt=ϕ(a). This is, in fact, the case. Also, since b≤Pa, we need ϕ(b)=t≤Qt=ϕ(a). This is also true.
Negative example
%%comment: dot source: digraph G { node [width = 0.1, height = 0.1] rankdir = BT; rank = same; compound = true; fontname="MathJax_Main"; subgraph cluster_P { node [style=filled,color=white]; edge [arrowhead = "none"]; style = filled; color = lightgrey; fontcolor = black; label = "P"; labelloc = b; a -> b; } subgraph cluster_Q { node [style=filled]; edge [arrowhead = "none"]; color = black; fontcolor = black; label= "Q"; labelloc = b; w -> u; w -> v; u -> t; v -> t; } edge [color = blue, style = dashed] fontcolor = blue; label = "φ"; labelloc = t; b -> u [constraint = false]; a -> v [constraint = false]; } %%
Here is an example of another map ϕ between two other posets P and Q. This map is not monotone, because a≤Pb while ϕ(a)=v∥Qu=ϕ(b).
Additional material
For some examples of montone functions and their applications, see Monotone function: examples. To test your knowledge of monotone functions, head on over to Monotone function: exercises.