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anchorContext: 'The other thing that this interpretation tells us is that the digit worth exactly half an $n$\\-digit is the $\\sqrt{n}$\\-digit, both because \\(1\\) if you want to use an $n$\\-digit to store two $x$\\-messages for some $x$, you need $x \\cdot x$ to be at most $n$; and \\(2\\) if you have a 50% chance of getting to use an $n$\\-digit and a 50% chance of nothing, then that's equivalent on average to a certainty of a $\\sqrt{n}$\\-digit\\.',
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