Note also that a cycle's inverse is extremely easy to find: the inverse of $~$(a\_1 a\_2 \\dots a\_k)$~$ is $~$(a\_k a\_{k-1} \\dots a\_1)$~$\.
I'm curious if the inverse has any particular use in this field.
by Alexei Andreev Jun 14 2016
Note also that a cycle's inverse is extremely easy to find: the inverse of $~$(a\_1 a\_2 \\dots a\_k)$~$ is $~$(a\_k a\_{k-1} \\dots a\_1)$~$\.
I'm curious if the inverse has any particular use in this field.
Comments
Patrick Stevens
None that I'm aware of, but I've found it convenient to know when I was doing exercises in a first course in group theory.