Let H be a subgroup of G. Then for any two left cosets of H in G, there is a Bijective function between the two cosets.
Proof
Let aH,bH be two cosets. Define the function f:aH→bH by x↦ba−1x.
This has the correct codomain: if x∈aH (so x=ah, say), then ba−1ax=bx so f(x)∈bH.
The function is injective: if ba−1x=ba−1y then (pre-multiplying both sides by ab−1) we obtain x=y.
The function is surjective: given bh∈bH, we want to find x∈aH such that f(x)=bh. Let x=ah to obtain f(x)=ba−1ah=bh, as required.